Mat126 Week 3 Assignment

Week 3 Assignment Erica Bass MAT126- fall over of numerical Methods Ali Choudry July 2, 2012 Week 3 Assignment Project # 1- I will judge to solve quadratic comparisons using an fire method which derived from India. soulfulness (possibly in seventh-century India) was solving a cover of quadratic comparisons by completing the square toes. At both(prenominal) point, he noticed that he was always doing the conduct equivalent steps in the exact same ensnare for both equation. Taking advantage of the genius of the great powers and benefits of algebra (namely, the ability to process with abstractions, rather than having to muck more or less with the come every single time), he made a mandate out of what hed been doing: (http://www.purplemath.com/modules/solvquad4.htm) (A) X2 2x 13 = 0 (a) Move the constant termination to the even off emplacement of the equation X2-2x-13 = 0 number 13 to each font of the equation to move 13 to the right nerve X2 - 2x 13 + 13 = 0+13 X2 2x = 13 (b) Multiply each term in the equation by four time the coefficient of the x2 term. Divide the coefficient of -2x by 2 -2/2 = -1 (c) Square the coefficient of the original x term and rack up it to both(prenominal) faces of the equation Square the result (-1)2 = 1 take this apprize to each side of the equation. This means that you will add 1 to each side of the equation.

X2 - 2x + 1 = 13-1 X2 2x+1 = 14 The conclude for moving the 13 to the right side of the equation, and then adding the 1 to each side of the equation is: Changing the leave side of the equation so it offer be factored as ! a perfect square. X2 - 2x + 1 = 14 (x-1)(x-1) = 14 (x-1)2 = 14 (c) here and now the square root of each side of the equation (d) sign the square root of each side of the equation ?(x-1)2 = ± ?(14) x-1= ±? (14) Add 1 to each side of the equation to remove the 1 from the left side of the equation. This leaves the variablke x as the only term on the left side of the equation. x-1+1=1±? (14) x = 1 ±? (14) (e) Set the left...If you want to get a good essay, order it on our website: OrderCustomPaper.com

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