Simplifying Expressions Essay Example for Free

Simplifying Expressions Essay entangle in this paper I have demonstrated the following solutions for the three problems listed below. Using th presumptuousness vocabulary words I have broken knock off each problem using the priggish steps in solving the algebraic expressions. Also shown will be what is important about authorized numbers and in what way they argon useful in using real numbers in solving algebraic expressions. By happy chance down the equation you can simplify the equation down to lowest wrong. Gathering the like terms in the equation is a step in breaking down the expression correctly. Take the coefficient and multiply it by the variable. The distributive billet in the expression is the letter in the expression. When solving a algebraic expression you always remove the parenthesis first. A. )2a(-5 + a) + 4(a + -5) Simplify the terms (-5 * 2a + a * 2a) + 4(a + -5) (-10a + 2a2) + 4(a + -5) -10a + 2a2 + 4(-5 + a)Reorder the terms -10a + 2a2 + (-5 * 4 + a * 4) -10a + 2a2 + (-20 + 4a) -10a + 4a = -6a -20 + -6a + 2a2 agree the like terms -20 + -6a + 2a2 a = 5This is the simplified roota = -2, 5 B. ) 2w 3 + 3(w 4) 5(w 6)The given expression -3 + -12 + 30 + 2w + 3w + -5wThe distributive property removes the parentheses. -15 + 30 + 2w + 3w + -5w Combine the like terms 15 + 2w + 3w + -5w = 0Combine the like terms 2w + 3w = 5wCombine like terms again 15 + 5w + -5w 5w + -5w 15 + 0 15 = 0The final answer C. ) 0. 05(0. 3m + 35n) + -0. 8(-0. 09n + -22m) (0. 3m * 0. 05 + 35n * 0. 05) + -0. 8(-0. 09n + -22m) (0. 015m + 1. 75n) + -0. 8(-0. 09n + -22m) 0. 015m + 1. 75n + -0. 8(-22m + -0.09n)Reorder the terms 0. 015m + 1. 75n + (-22m * -0. 8 + -0. 09n * -0. 8) 0. 015m + 1. 75n + (17. 6m + 0. 072n) 0. 015m + 17. 60. 1034345728n m + 1. 75n + 0. 072n The distributive property removes the parentheses 0. 015m + 17. 6m = 17. 615mCombine the like terms 17. 615m + 1. 75n + 0. 072n 1. 75n + 0. 072n = 1. 822nCombine the like terms 17. 615m + 1. 822n 17. 615 m + 1. 822n Solving Move solely terms containing m to the left, all other terms to the right. Add -1. 822n to each side of the equation. 17.615m + 1. 822n + -1. 822n = 0 + -1. 822n Combine like terms 1. 822n + -1. 822n = 0. 000 17. 615m + 0. 000 = 0 + -1. 822n 17. 615m = 0 + -1. 822n Remove the zero 17. 615m = -1. 822nDivide each side by 17. 615. m = -0. 1034345728n Simplifying m = -0. 1034345728n How are the real numbers useful in solving algebraic expressions? The real number line is a graph that is used to represent the set of real numbers. Using real numbers is useful by charting them on the graph helps to solve the algebraic expression.